Explain the preparation of alkenes by the hydrogenation of alkynes with examples.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Alkenes can be prepared from alkynes by partial hydrogenation using specific catalysts:
$(a)$ Formation of $cis$-alkene:
Alkynes on partial reduction with dihydrogen in the presence of Lindlar's catalyst (palladised charcoal partially deactivated with poisons like sulphur compounds or quinoline) give $cis$-alkenes.
General reaction: $RC \equiv CR' + H_2 \xrightarrow{Pd/C, \text{poison}} \text{cis-alkene}$
Example: $CH_3-C \equiv C-CH_3 + H_2 \xrightarrow{Pd/C, \text{poison}} \text{cis-but-2-ene}$
$(b)$ Formation of $trans$-alkene (Birch Reduction):
Alkynes on reduction with sodium in liquid ammonia $(Na/NH_3(l))$ give $trans$-alkenes.
General reaction: $RC \equiv CR' + H_2 \xrightarrow{Na/NH_3(l)} \text{trans-alkene}$
Example: $CH_3-C \equiv C-CH_3 + H_2 \xrightarrow{Na/NH_3(l)} \text{trans-but-2-ene}$

Explore More

Similar Questions

Which method can be used to prepare $Propane$ from $Propene$?

Addition of $OsO_4$ to cyclopentene would give a product which is

The compound $CH_3-C(CH_3)=CH-CH_3$ on reaction with $NaIO_4$ in the presence of $KMnO_4$ gives:

Alkene $R-CH=CH_2$ reacts readily with $B_2H_6$ and the product on oxidation with alkaline hydrogen peroxide produces:

The main product of the following reaction $(1 \ mol)$ will be:
$C_6H_5-CH_2-CH=CH_2 + HBr \rightarrow \text{Products}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo